A, B and C can complete a work in 12 days, 18 days and 6 days respectively. They
began the work together but B and C left after 2 days. How long will A take to
complete the remaining work?
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Class 11
>>Applied Mathematics
>>Numerical Applications
>>Time and work
>>A, B and C can do a piece of work in 15,
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A,B and C can do a piece of work in 15,12 and 20 days respectively. They started the work together, but C left after 2 days. In how many days will the remaining work be competed by A and B?
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Solution
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Work is done by A in one day =
15
1
By B=
12
1
C=
20
1
Together in 1 Day =
15
1
+
12
1
+
20
1
=
60
4+5+3
=
60
12
=
5
1
2 days work =
5
2
Remaining work = 1−
5
2
=
5
3
one day work of A,B ⇒A+B=
15
1
+
12
1
=
60
4+5
=
60
9
=
20
3
(A+B) work for t days =
20
3
t=
5
3
t=4 days
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