A,B and C can do a piece of work in 10,12,and 25 days respectively after 3 days B left the work in how many days the remaining work will be completed by A and C
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Answered by
1
Answer:
Yar bhat hard ha thora Assan pucho
Answered by
3
Answer:
Per the question:
10A=1
12B=1 and
25C=1
Then:
300A=30
300B=25
300C=12
So:
300(A+B+C)=30+25+12=67
300/67(A+B+C)=1
After 3 days, the amount of work done would be:
3 x 67/300=201/300
So 99/300, or 33/100ths of the work is left. A and C, together can do:
50A=5
50C=2
50(A+C)=5+2=7
A+C=7/50ths of the work per day
Then:
33/100 / 7/50=33/100 x 50/7=33/14 days before A and C, working together, can finish the work
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