Math, asked by bkgzp7272, 5 months ago

A,B and C can do a piece of work in 10,12,and 25 days respectively after 3 days B left the work in how many days the remaining work will be completed by A and C

Answers

Answered by hamzashahrukh136
1

Answer:

Yar bhat hard ha thora Assan pucho

Answered by ManuShreeDaryani
3

Answer:

Per the question:

10A=1

12B=1 and

25C=1

Then:

300A=30

300B=25

300C=12

So:

300(A+B+C)=30+25+12=67

300/67(A+B+C)=1

After 3 days, the amount of work done would be:

3 x 67/300=201/300

So 99/300, or 33/100ths of the work is left. A and C, together can do:

50A=5

50C=2

50(A+C)=5+2=7

A+C=7/50ths of the work per day

Then:

33/100 / 7/50=33/100 x 50/7=33/14 days before A and C, working together, can finish the work

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