Question

A, B and C can do a piece of work in 10 days, 12 days and 15 days respectively. How long will they take to finish it if they work together?​

Answer 1

Answer:

Well let’s see how much work they can do in 1 day

A can do 1/12 of that

B can do 1/15

and C can do 1/10

So all of them working together in one day they will manage to finish

112+115+110=  

560+460+660=  

1560=14  

So if they work all together they will do 1/4 th of the work in one day

Therefore they will need 4 days to finish it all !

Step-by-step explanation:

branliest ??

Answer 2

Let the work be completed in x days.

A's 1 days' work = 1/10

⇒A's (x−5) days' work = (x-5)/10

B's 1 days' work = 1/12

⇒B's (x−3) days' work = (x−3)/12

C's 1 days' work = 1/15

⇒C's x days' work = x/15

$⇒ \frac{x - 5}{10} + \frac{x - 3}{12} + \frac{x }{12} = 1$

$⇒ \frac{6(x−5)+5(x−3)+4x}{60} = 1$

⇒6x−30+5x−15+4x=60

⇒15x=60+45=105⇒x=7

∴ The work was completed in 7 days.