Question

A B and C can do a piece of work in 10 days A alone can do it in 40 days and B can do it in 30 days in how many days will see alone do the same work

Answer 1

c alone 24 days
1/40+1/30+c=1/10
c=1/10-1/40-1/30
c=(12-3-4)/120
c=5/120=1/24
c alone is 24 days

Answer 2

hey there is answer !!
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A and B takes 4 days to complete work = x

A and B takes 1 day to complete work = x/4

A alone takes 12 days to complete the work= x

A alone takes 1 day to complete the work = x/12

Now

work done by B alone in one day is

 x/4 - x/12 = 3x -x /12

therefore 1/6x

∴ work done by B alone in 6 days= 1/6x ×6

 = x

Hence it will take 6 days by B alone to complete the same