Question

A b and c can do a piece of work in 11 days 20 days respectively working alone

Answer 1

LCM(11,20,55) = 220.

Let total work is 220 units such that,

Work done by A in 1 day =

220

11

=

20

units

Work done by B in 1 day =

220

20

=

11

units

Work done by C in 1 day =

220

55

=

4

units

First day, A and B work and completes 20+11=31 units of work

Second day, A and C work and completes 20+4=24 units of work

So, in every 2 days, 31+24=55 units of work gets completed.

in 8 days, 4×55=220 units of work gets completed.

Therefore, ans is 8 days

Hope it helps ✌✌❤

Answer 2

hope it works ✌

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