A, B and C can do a piece of work in 14, 28 and 42 days respectively. They all start doing the work together. A continues to do the work until it is completed, C left 2 days before the work was completed, and B left 1 day before the work was completed. In how many days the work was completed?
Answers
Answer:
a works 14 days and B work 27 days and c works 40 days and the total days they worked is equals to 14 + 27 + 40 equals to 81 days the totally worked
Step-by-step explanation:
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Work will be completed in approximate 8.3 Days
Given:
A, B and C can do a piece of work in 14, 28 and 42 days respectively.
They all start doing the work together.
A continues to do the work until it is completed
B left 1 day before the work was completed
C left 2 days before the work was completed
To Find:
In how many days the work was completed?
Solution:
A can do work in 14 Days
=> A's 1 day work = 1/14
B can do work in 28 Days
=> B's 1 day work = 1/28
C can do work in 14 Days
=> C's 1 day work = 1/42
Let say work completed in d days
A worked for d days
B worked for d - 1 days
C worked for d - 2 days
A work in d days = d/14
B work in d-1 days = (d-1)/28
C work in d-2 days = (d-2)/42
Total work = d/14 + (d-1)/28 + (d-2)/42 = 1
=> 6d + 3(d - 1) + 2(d - 2) = 84
=> 11d - 7 = 84
=> 11d = 91
=> d = 91/11
=> d ≈ 8.3
Work will be completed in approximate 8.3 Days
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