A B and C can do a piece of work in 15 12 and 20 days respectively they started the work together but C left two days in how many days will the remaining work be completed by a and b
Answers
Answered by
0
Answer:
1/15+1/12+1/20=(4+5+3)/60=12÷60=1/5 they did 2 days so 2/5 work completed and remaining work is 3/5 is done by A B so 2/5×(1/15+1/20)=2/5×60/7 is the answer
Similar questions