A B and C can do a piece of work in 15 12 and 20 days respectively. They started the work together, but C left after 2 days. In how many days will the remaining work be completed by
A and B?
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Answer:
In 1- day A,B and C can do =1/12+1/15+1/20 = 12/60= 1/5 work
In 2- days they do= 2/5 work.
In 1-day A +B can do= 1/12+1/15 =9/60
So the remaining 3/5 of the work can be done by A and B in
=(3/5)÷(9/60) = 4 days
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