A, B and C can do a piece of work in 15, 12 and 20 days respectively.
They started the work together, but Cleft after 2 days. In how many
days was the remaining work completed?
(2)
Answers
Answered by
7
Answer:
4 days...
Step-by-step explanation:
a+b+c (1day)=1/15+1/12+1/20
=12/60=1/5
a+b+c(2 day)=2/5
then c left
remaining work 1-2/5=3/5
remaining work to be finished by a and b
a+b together can do the whole work in 15*12/(15+12)
=20/3 days
a+b together can do the 3/5 th of work in 20/3*3/5= 4
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