A, B and C can do a piece of work in 15, 12 and 20 days respectively. They started the work together, but C left after 2 days. In how many days will the renaining work be completed by A and B together?
Answers
Answered by
0
Work is done by A in one day =151
By B=121
C=201
Together in 1 Day =151+121+201=604+5+3=6012=51
2 days work = 52
Remaining work = 1−52=53
one day work of A,B ⇒A+B=151+121=604+5=609=203
(A+B) work for t days = 203t=
Answered by
3
ANSWER
Work is done by A in one day =
15
1
By B=
12
1
C=
20
1
Together in 1 Day =
15
1
+
12
1
+
20
1
=
60
4+5+3
=
60
12
=
5
1
2 days work =
5
2
Remaining work = 1−
5
2
=
5
3
one day work of A,B ⇒A+B=
15
1
+
12
1
=
60
4+5
=
60
9
=
20
3
(A+B) work for t days =
20
3
t=
5
3
t=4 days
A and B will complete the work in 4 days.
hope it helps u dear.....
#itzcrazypie
Similar questions