Math, asked by krithikah, 2 months ago

A, B and C can do a piece of work in 15,12 and 20 days, respectively. They
started the work together, but C left after days. In how many days will the
remaining work be completed by A and B?

Answers

Answered by llNidhill
7

Given↷

  • A, B and C can do a piece of work in 15,12 and 20 days, respectively.

To find↷

  • How many days will the
  • remaining work be completed by A and B?

Solution↷

 \sf \: One \: Day \: of \: A =  \frac{1}{15}  \\  \sf \: One \: Day \: of \: B =  \frac{1}{12}  \\  \sf \: One \: Day \: of \: C =  \frac{1}{20}  \\  \sf \: One \: Day \: of \: A, \: B, \: C \\  =  \frac{1}{12}  +  \frac{1}{20}  +  \frac{1}{15}  \\  =  \frac{5 + 3 + 4}{60}  =  \frac{12}{60}  \\  \frac{1}{5}  \\  \sf \: Two \: Days \: Work \: of \: A, \: B,\: C =  2 \times  \frac{1}{5}  =  \frac{2}{5}   \\  \sf \: Remaining \: Work = 1 -  \frac{2}{5}  \\  \:  \:  \:  \:  =  \frac{3}{5}  \\ \sf \: Combine \: Work \: of \: A, \: B \:  =  \frac{1}{15}  +  \frac{1}{12}  \\  =  \frac{4 + 5}{60}  \\  =  \frac{9}{60}  =  \frac{3}{20} \\  \sf \: number \: of \: days \: Will \: Be \: Remaining \\ \sf Work \: Be  \: Competely \: by \: A \: And \: B \\  =  \frac{3}{5}  \times  \frac{20}{3}  \\ \mathscr  = 4 \: Days

Similar questions