A, B and C can do a piece of work in 15,12 and 20 days, respectively. They
started the work together, but C left after days. In how many days will the
remaining work be completed by A and B?
Answers
Answered by
6
Answer:
4
Step-by-step explanation:
one day's work
=a+b+c
=1/15+1/12+1/20
=1/5
2 day's work of a,b,c together
=2×1/5
=2/5
Remaining work
=1-2/5
=3/5
Combine work of both a,b
=1/15+1/12
=3/20
The no. of days taken by a,b to finish the remaining work
=3/5÷3/20
=4
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