A, B and C can do a piece of work in 15, 12 and 20 days respectively. They began to work,
but C left after working for 2 days. How many days will be needed to complete the
remaining work?
Answers
Answered by
0
Answer:
4 days
Step-by-step explanation:
Work is done by A in one day =
15
1
By B=
12
1
C=
20
1
Together in 1 Day =
15
1
+
12
1
+
20
1
=
60
4+5+3
=
60
12
=
5
1
2 days work =
5
2
Remaining work = 1−
5
2
=
5
3
one day work of A,B ⇒A+B=
15
1
+
12
1
=
60
4+5
=
60
9
=
20
3
(A+B) work for t days =
20
3
t=
5
3
t=4 days
A and B will complete the work in 4 days.
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