A,B and C can do a piece of work in 15,12 and 20 days respectively.Theystarted the work together,But C left after 2 days.In how many days will the remaining work be completed by A and B?
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A --------15 days
B---------12 days
C---------20 days , L.C.M of 15,12,20= 60 means total work is 60 unit.
A's 1 day work ------- 4 unit
B's 1 day work -------5 unit
C's 1 day work -------3 unit
if they work together then
(A+B+C) 's 1 day work ------- = 4+5+3 = 12 unit
they work together till 2 days so 2 days work= 12×2=24 unit and then C left.
now remaining work = 60-24 = 36 unit
now A+B have to complete the 36 unit work.
because (A+B) 's 1 day work ------- = 4+5 = 9 unit
then for 36 unit they will take 36/9 = 4 days.
B---------12 days
C---------20 days , L.C.M of 15,12,20= 60 means total work is 60 unit.
A's 1 day work ------- 4 unit
B's 1 day work -------5 unit
C's 1 day work -------3 unit
if they work together then
(A+B+C) 's 1 day work ------- = 4+5+3 = 12 unit
they work together till 2 days so 2 days work= 12×2=24 unit and then C left.
now remaining work = 60-24 = 36 unit
now A+B have to complete the 36 unit work.
because (A+B) 's 1 day work ------- = 4+5 = 9 unit
then for 36 unit they will take 36/9 = 4 days.
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Step-by-step explanation:
Adding 8 to 7 results in a sum of digits of 6, and so on down to adding 8 to 1 which gives 9.
...
Number Repeating Cycle of Sum of Digits of Multiples
10 {1,2,3,4,5,6,7,8,9}
11 {2,4,6,8,1,3,5,7,9}
12 {3,6,9,3,6,9,3,6,9}
13 {4,8,3,7,2,6,1,5,9
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