A, b and c can do a piece of work in 20, 30 and 60 days respectively. in how many days can a do the work if he is assisted by b and c on every third day? 12 days 15 days 16 days 18 days
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Let total work be 1
then Work done by A in 1 day = 1/20 ( Total work / days to complete it)
B = 1/30
C = 1/60
Total work A , B , C can do in 1 day = 1/10(add up all workdone by A,B,C)
Work done By A in 2 days = 1/20 × 2 = 1/10
Total work done in 3 Days = 1/10 + 1/10 = 1/5 ( 2 days A and 3rd days A,B,C)
1/5 × Y days = 1 ( total work will be done in Y days)
Y = 5days....but 1/5 work is done in 3 days
so total days = 15 days ( 3×5).
Hope you understand it
if you like the answer plz mark it brainleist.
then Work done by A in 1 day = 1/20 ( Total work / days to complete it)
B = 1/30
C = 1/60
Total work A , B , C can do in 1 day = 1/10(add up all workdone by A,B,C)
Work done By A in 2 days = 1/20 × 2 = 1/10
Total work done in 3 Days = 1/10 + 1/10 = 1/5 ( 2 days A and 3rd days A,B,C)
1/5 × Y days = 1 ( total work will be done in Y days)
Y = 5days....but 1/5 work is done in 3 days
so total days = 15 days ( 3×5).
Hope you understand it
if you like the answer plz mark it brainleist.
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