A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
Answers
Answered by
6
Answer:
hlo
your answer is here !
Step-by-step explanation:
One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.
C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.
Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.
Remaining Work = 7/10, which was done by A,B and C in the initial number of days.
Number of days required for this initial work = 7 days.
Thus, the total numbers of days required = 4 + 7 = 11 days.
Answered by
2
Answer:
Step-by-step explanation:
A 24 5
B 30 120 4
C 40 3
Work done by A+B in 4 days = 9*4 =36
Remaining 120-36 =84
84 work is done by A+B+C in
84/12 = 7 days
Total =7 +4 =11 days
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