A,B and C can do a piece of work in 3,4, and 6 days respectively . if a left before 2 days and B joined after 3 days in how many days will the work be completed ?
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Step-by-step explanation:
1day work of A = 1/3
1day work of B =1/4
1day work of C =1/6
Total work of A,B,C in 1 day = 1/3+1/4+1/6
= 3/4
since A left after working 2days
so , work done by A in 2 days = 1/3*2
= 2/3
work done left by B in 3 days = 1/4*3
=3/4
so, work would be completed in = 4/3*2/3*3/4
=2/3 days
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