Question

A B and C can do a piece of work in 5 days.A can do the work in 10 days.B can do the work in 12 days.In how many days C do the work?

Answer 1

Here's your answer!!

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(A +B+C )can do piece of work in 5 days.

(A+B+C)'s one day work =
$= > \frac{1}{5}$

A can of a piece of work in 10 days.
One day work of A =
$= > \frac{1}{10}$
B can do a piece of work in 12 days
One day work of B =
$= > \frac{1}{12}$
Let the one day work be C be x

A/q

$= > \frac{1}{10} + \frac{1}{12} + x = \frac{1}{5} \\ = > ( \frac{6 + 5}{60}) + x = \frac{1}{5}$
$= > \frac{11}{60} + x = \frac{1}{5} \\ = > x = \frac{1}{5} - \frac{11}{60}$
$= > x = \frac{12 - 11}{60} \\ = > x = \frac{1}{16}$
Hence,
One day work of C =
$= > \frac{1}{60}$
And C can complete it in 60 days.

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Hope it helps you !! :)

Answer 2

AB and C can do a peice of work in 1/5 days
A can do a peice of work in 1/10 days
B can do apeice of work in 1/12 days
AB can do a piece of work in 11/60 days
C can do a peice of work in 1/5-11/60
C can do work in 60 days