A,B and C can do a piece work in 10 12 and 15 days respectively .They work for some days.A leaves before 5 days before the completion of the work and B leaves two days after A.how long does the whole work last
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Step-by-step explanation:
LCM of 10,12,15 is 60
Efficiency of A = 60/10= 6
Efficiency of B = 60/12= 5
Efficiency of C = 60/15= 4
In last 3 days only C works= 3*4= 12
Before 2 Days B+C worked =2*9= 18
Remaining by A+B+C =60-30=30
30/15=2 days
Total= 5-2=7 days
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