A, B and C can do a work in 12, 15 and 20<br />days respectively. All three started together<br />but C left in between before completion of<br />work. The remaining work was completed<br />by A and B and the total work was<br />completed in 6 days. Find after how many<br />days C left the work? 1)2 2)3 3) 4 4) 1 5)5
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Answer:
2 days
A : B : C
12:15:20
<60>
5:4:3
work was completed in 6 days
in these days A and B was continually working it means
5+4= 9 units was completed per day by A and B
then
in 6 days = 6×9=54 unit
rest of units done by C
60-54=6
C's efficiency 3 unit per day
C completed 6 unit by = 6÷3= 2 days
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