A,B and C can do a work in 12,24 and 8 days respectively . They all work for one day . Then C leaves the group . In how many days will A and B complete the rest of the work?
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Answer:
ans : 6 days
Step-by-step explanation:
given a = 1/12 , b = 1/24 and c = 1/8 , to find the work done by a,b and c.
given a,b and c work for 3 days so,take as (a+b+c)*3=( 1/12+1/24+1/8)*3
take LCM for 12,24 and 8 then denominator will be 24.
1/12+1/24+1/8 = 2+1+3/24 = 6/24 = 1/4
so 1/4 of the work done by a,b and c. remaining work done by a and b will be = 1- 1/4
= 4-1/4
= 3/4 of the work done by a and b . given that c leaves ,so remaining only a and b , (a+b)*x = 3/4
=> (1/12+ 1/24 )*x = 3/4 take LCM for 12,24 ,denominator will be 24
=> 3/24*x = 3/4 => 3*x = 24*3/4 => 3*x = 18 then x= 6 i.e ans will be 6 days.
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