A, b and c can do a work in 15 days. The start together. When work is done a leave the work. Now the work will take 4 days more to be completed. When of the work is done b leave the work. Now the work will take 2 days more to be completed. In how many days c can complete the whole work.
Answers
Answered by
0
Answer:
m = 55/5= 11 days.
Step-by-step explanation:
There are multiple ways of doing this :
Method 1
A & B together can complete work in (25x20)/(25+20) =500/45 = 100/9 days.
They complete 5 x 9/100= 9/20 work in 5 days.
Remaining 11/20 work done by B in 11/20 x 20 = 11 days.
Method 2
A works only for 5 days completing 5/25 = 1/5 part of work.
Remaining 4/5 work is done by B in 4/5 x 20 = 16 days.
=> B works for 11 days after A leaves.
Method 3
Let B take m days after A leaves.
Since A & B work together for 5 days, we have :
5/25 + (5 + m)/20 = 1
Taking LCM as 100,
20+ 5(5 + m) = 100
=> 20 + 25 + 5m = 100
5m = 100 - 45 = 55
m = 55/5= 11 days.
Similar questions