A, B, and C can do a work in 20, 45, and 120 days,
respectively. They started the work. A left 10 days
before and B left 5 days before the completion of
work. In how many days is the total work completed?
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Answer:
Let the work be completed in N-days.
So (N-10)/20 + (N-5)/45 + N/120= 1
So (N-10)18 + (N-5)8 +3N=360
29N= 580
So N= 20
Therefore the whole work was completed in 20- days.
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