A,B and C can do a work in 8 min. To address a pile of envelopes. A and B together would take 10 mins;A and C would take 15 min. How long would each take to do it alone?
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1
Answer:
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Step-by-step explanation:
Work done by A in 1 day=
8
1
Work done by B in 1 day=
10
1
Work done by C in 1 day=
15
1
Work done by A and B together in 1 day=
8
1
+
10
1
=
40
5+4
=
40
9
∴ In 2 days A and B complete 2×
40
9
=
20
9
of work
Work remaining =1−
20
9
=
20
11
Work done by B and C together in 1 day
=
10
1
+
15
1
=
30
3+2
=
30
5
=
6
1
Let no. of days be n.
∴n×
6
1
=
20
11
n=
20
11
×6=
10
33
days
Total no. of days =(2+
10
33
)=
10
53
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