Math, asked by vittitrushna138, 7 hours ago

A, B and C can do a work separately in 40, 50
and 75 days respectively. B and C work first
for 10 days and leave. How many more days
will A alone take to complete the remaining
work?​

Answers

Answered by rishabhpurchase2002
1

Answer:

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Step-by-step explanation:

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Answered by barmanbhanita96
3

Answer:

B & C in 10 days do 10/50 + 10/75 = 1/5 + 2/15 = 5/15 =1/3

Work remaining = 2/3

A will take 2/3 x 40 = 80/3= 26.67 days ANSWER

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