Question

A, B and C can do a work together in a certain number of days. If A leaves after half the work is done, then the work takes 4 more days for completion, but if B leaves after half the work is done, the work takes 5 more days for completion. If A takes 10 more days than B to do the work alone, then in how many days can C alone do the work? ​

Answer 1

Answer:

As efficiency×time =work

Let total work be 40 units

As A+B+C completed the whole work in 40 days

So efficiency of A+B+C =1

Now they work for 16 days so they completed 16 units of work

Total work remaining =40-16=24 units

This work is finished by B+C in 40 days

B+C efficiency =24/40=3/5 units

So A effiency =1-3/5=2/5 units

So A completed the whole work alone in 40÷2/5=100 days