A, B and C can finish a piece of work in 20 days, 30 days and 40 days respectively. They started together but A left after 3 days and Cleft 2 days before the completion of work. Calculate number of days in which the work is completed.
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Answer:
A= 23 days B= 30 days C = 42 days
Step-by-step explanation:
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Answer:
Step-by-step explanation:
total work=120
In first three days work=3(6+4+3)=39 (up to A is left)
C left before 2day compete the work=4*2=8 ( B work alone)
39+8=47 120-47=73 73/7=10.4
total days=10+3+2=15
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