A, B and C can finish a work 15,12 and 20 days respectively. They started the work together, but C left after 2 days. In how many days will the remaining work be completed by A and B?
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Step-by-step explanation:
In 1 day, A can do 1/15, B can do 1/12 and C can do 1/20 of the work. (Given)
So, work done by all three of them in 1 day=1/15+1/12+1/20=(4+5+3)60=12/60 =1/5 part.
In 2 days, total work done= 2/5.
Remaining work=3/5
Now, work done by A and B in 1 day= 1/15+1/12=9/60=3/20.
Therefore, number of days required to do the remaining work by A and B= 20/3×3/520/5=4
So, in 6 days, A and B will complete the remaining work.
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