A, B and C complete a certain work in 6, 8 and 12 days respectively. In how many days would all of them complete the work if they work together?
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Answer:
2 + 2/3 days
Step-by-step explanation:
consider total work as lcm of 6,8,12 days i.e. 24
efficiency of A = 24/6 = 4 unit / day
efficiency of B = 24/ 8 = 3 unit / day
efficiency of C = 24/12 = 2 unit/day
from above total work done by A, B, C together
= 4+3+2= 9unit /day
therefore total days required
= 24/9
= (2+6/9)days
= (2+2/3) days
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