A, B and C complete a work in alternate way. If A starts the work followed by B and C then the work gets completed in 38 days but if B starts then the work is completed in 38 days and if C starts it then the work gets completed in 38 days. Find in how many days A alone can complete the work
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A alone can finish the work in 48 days
A’s one day work = 1/48
A and B complete the whole work in = days
A and B work on alternate days, with B beginning so, we can say B will work only 6 days A will work only days
If A’s one day work = 1/48 of work A complete in = 1 days
A’s days work =
Remaining work = 1 – [1/9] = 8/9
B complete 8/9 work in = 6 days
⇒ B complete whole work in = 6 × [9/8] = 27/4 days
⇒ B alone can finish 4 times the same work in = [27/4] × 4 = 27 days
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