A, B and C do a piece of work in 15, 12 and 20 days respectively.they started the work together ,but C left after 2 days. In how many days will the remaining work be completed by A and B
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A B C
15 12 20
LCM(15,12,20) = Total Work
= 60
A B C
15 12 20
Work done in 1 day 4 5 3
Work done by all three in 1 day = A + B + C = 4 + 5 +3 = 12
C left after 2 days
Therefore work done in 2 days = 2 * (A+B+C) = 24
Remaining work = 60 - 24 = 36
This remaining work has to done by A and B because C has left
Work done by A + B in 1 day = 9
Number of days = 36/9 = 4 days
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