a,b and c do a piece of work in 20,30 and 60 days respectively in how many days can a do the work if he is assisted by b and c on every third day ?
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Answer:
20 days
Step-by-step explanation:
a,b,c can do in 20,30,60
LCM is 60 = 60p
a can complete in 60p/20=3p
b can complete in 60p/30=2p
c can complete in 60p/60=1p
a has to do for first 2 days:
3p=1day
6p=2days
b and c in third day
2p+1p=>3p=1 day
total 9 p for 3 days
54 p for 18 days
remaining 6p for a,b,c 2days
total 54p+6p=>60 p
18+2=20days
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