Question

A , B and C form a triangle where ∠ B A C = 90 ∘ . A B = 4 mm and B C = 14.8 mm. Find the length of A C , giving your answer rounded to 1 decimal place

Answer 1

Answer:

The length of BC would be 12.2 mm.

Step-by-step explanation:

Given,

In triangle ABC,

∠BAC = 90°,

Thus by the Pythagoras theorem,

BC^2=AB^2 + CA^2BC

2

=AB

2

+CA

2

We have,

AB = 9.6 mm and CA = 7.6 mm,

By substituting the values,

BC^2 = 9.6^2 + 7.6^2 =92.16+ 57.76= 149.92BC

2

=9.6

2

+7.6

2

=92.16+57.76=149.92

\implies BC = 12.24418\approx 12.2\text{ mm}⟹BC=12.24418≈12.2 mm

Step-by-step explanation:

sorry I did it wrong sry I did not understand the question

Answer 2

Answer:

14.2

Step-by-step explanation:

In Triangle ABC angleA=90°

According to pythagorean Theorem

BC^2=(AB)^2+(AC)^2

14.8^2=4^2+ AC^2 (AB=4mm and BC=14.8mm)

203.40=AC^2

AC=root over 203.40

AC=14.2 mm ( Rounded to one decimal Point )

Hope it helps you