Question

A, B and C have total Rs. 4600. The ratio of the money between B and C is 3: 5. If the share of A is Rs. 1400 the find the shares of B and C whose share is the minimum ​

Answer 1

4600:1400
2300:700
1150:350
230:70
23:7

ANSWER: 23:7


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Answer 2

Answer:

If the ratio of the money between B and C is 3:5, then we can represent their shares as 3x and 5x, respectively.

So, the total share of B and C combined is 3x + 5x = 8x.

We know that the total amount of money is Rs. 4600, and A's share is Rs. 1400.

Therefore, the combined share of B and C is Rs. 4600 - Rs. 1400 = Rs. 3200.

We can now set up an equation to find the value of x:

5x/(3x + 5x) = 5/8

Simplifying this equation, we get:

5x = (5/8) * (3x + 5x)

5x = (15/8)x + (25/8)x

5x - (15/8)x = (25/8)x

(40/8)x - (15/8)x = (25/8)x

(25/8)x = Rs. 800

x = (8/25) * Rs. 800

x = Rs. 256

So, B's share is 3x = 3 * Rs. 256 = Rs. 768

C's share is 5x = 5 * Rs. 256 = Rs. 1280

Therefore, the minimum shares of B and C are Rs. 768 and Rs. 1280, respectively.