Question

A, B and C individually can do a certain work in 12, 16 and 24 days resp. B and C work together for 4 days and then A takes C's place? In how many days the whole work will be finished?​

Answer 1

Answer:

and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they wil complete the same work in :

[A]4 days

[B]$latex \frac{1}{4}&s=1$ days

[C]$latex 3\frac{3}{7}&s=1$ days

[D]$latex \frac{7}{24}&s=1$ days

$latex \mathbf{3\frac{3}{7}}&s=1$ days

A’s 1 day’s work = $latex \frac{1}{24}&s=1$

B’s 1 day’s work = $latex \frac{1}{6}&s=1$

C’s 1 day’s work = $latex \frac{1}{12}&s=1$

(A+B+C)’s 1 day’s work = $latex \frac{1}{24}+\frac{1}{6}+\frac{1}{12}=\frac{1+4+2}{24}=\frac{7}{24}&s=1$

∴ The work will be completed by them in $latex \frac{24}{7}&s=1$ i.e. $latex 3\frac{3}{7}&s=1$ days.