Question

A,B and C individually can do a work in 10 days. 12 days and 15 days respectively. If they start working together. then the number of days required to finish the work is ?​

Answer 1

Answer:

Assume, Total Work = 1

therefore,

A's work in 1 day= 1/10

B's work in 1day= 1/12

C's work in 1day = 1/15

A, B, C together in one day =

1/10 + 1/12+ 1/15

= (6+ 5+ 4) / 60

=15/60

= 1/4

A,B, C together will finish the work in,

1÷ 1/4

= 1× 4/1

= 4days

Step-by-step explanation:

Find the LCM of 10, 12,15.

If together they can do one-fourth of the work in 1 day,

then two-fourth in two days, three-fourth in 3 days and four-fourth (4/4=1) in 4 days.