A, B and C play a game and the chance of their winning it in an attempt are 1/3, 1/4 and 2/3
respectively. A has to start the game, followed by B and then by C. this cycle is repeated till one of them wins
the game. Find the probability of winning of B.
Answers
Answer:
3/11
Step-by-step explanation:
GIVEN THAT A=1/3
B=1/4
C=2/3
TOTAL NO, OF OUTCOMES = 1/3+1/4+2/3
=11/12
Therefore probability of winning B = 1/4
i.e no, of favorable outcome = 1/4
p(e) = No, of favorable outcome/ total no, of outcome
1/4 ÷ 11/12=
3/11
Hope it is usefull
Answer:
3/11
Step-by-step explanation:
GIVEN THAT A=1/3
B=1/4
C=2/3
TOTAL NO, OF OUTCOMES = 1/3+1/4+2/3
=11/12
Therefore probability of winning B = 1/4
i.e no, of favorable outcome = 1/4
p(e) = No, of favorable outcome/ total no, of outcome
1/4 ÷ 11/12=
3/11
Step-by-step explanation: