A B and C start cycling around a circular path in the same direction at the same time circumference of the path is 1980 if the speed of a is 330 metre per minute and they start from some point then after what time they will be together at the starting point
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Answer:
Step-by-step explanation:
A will complete one round in 1980/330 = 6 min
B will complete one round in 1980/198 = 10 min
C will complete one round in 1980/220 = 9 min
Now, let A, B and C meet after time t and they would have respectively completed, n1, n2 and n3 rounds and they would be be x distance away from the start point
Hence, 330t = x + 1980n1
198t = x + 1980n2
220t = x + 1980n3
Substituting x from equation 1 into 2 and 3
198t = 330t - 1980n1 + 1980n2
1980(n1-n2) = 132t
t = 15(n1-n2)
Also, 220t = 330t - 1980n1 + 1980n3
1980(n1-n3) = 110t
Since t is same, and n1-n3 and n1-n2 can be any whole number, so we need to compute LCM of 15 and 18 which is 90
Hence, A,B and C will meet after 90 min.
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