Question

a, b and c together can do a piece of work in 15 days B alone can do it in 30 days and C alone can do it in 40 days in how many days will a alone do the work

Answer 1

Here's your answer!!

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It's given

(A+B+C) can do a piece of work on 15 days.

(A+B+C)'s one day work =

$= > \frac{1}{15}$

B can do piece of work in 30 days

One day work of B

$= > \frac{1}{30}$

C can do the piece of work in 40 days

One day work of C

$= > \frac{1}{40}$

Let the A be complete the work in x days.

And one day work of A be

$= > \frac{1}{x}$

A/q

$= > a + b + c = {15}$

$= > \frac{1}{x} + \frac{1}{30} + \frac{1}{40} = \frac{1}{15}$

$= > \frac{1}{x} + ( \frac{4 + 3}{120} ) = \frac{1}{15}$

$= > \frac{1}{x} + \frac{7}{120} = \frac{1}{ 15}$

$= > \frac{1}{x} = \frac{1}{15} - \frac{7}{120}$

$= > \frac{1}{x} = (\frac{8 - 7}{120} )$

$= > \frac{1}{x} = \frac{1}{120}$

Hence,

A can alone complete the work in 120 days and one day of A is 1/120

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Hope it helps you!! :)