a b and c together can do a piece of work in 40 days after working with B and C for 16 days a leaves and then B and C complete the remaining work in 40 days more a alone can do the work in?
Answers
Answered by
6
Answer:
Step-by-step explanation:
Work done by A,B,C in 1 day = 1/40
Work done by A,B,C in 16 days
= 16/40 =2/5
Remaining work = 1 - 2/5
=3/5
.
This remaining work 3/ 5
is completed by B and C in 40 days.
Therefore work done by B and C in 1 day =(3/5) / 40 =3/ 200
Work done by A in 1 day
=1/40 − 3/200
= 1 /100
Therefore A alone can finish the work in 100 days.
hope it helps..
Similar questions