Question

A, b and c together can finish a piece of work in 12 days. a and c together work twice as much as b, a and b together work thrice as much as
c. in what time could each do it separetely?

Answer 1

12/a+12/36+12/48=1
12/a+1/3+1/4=1
12/a+7/12=1
12/a=1-7/12
12/a=12-7/12
12/a=5/12
a=12×12/5
a=28.8days
b=36days
c=48days

Answer 2

Step-by-step explanation:

A+B+C======36

Efficiency

A+B:C======8:4

A+C:B======9:3

C====4

B====3

A====5

Total work=12×12=144

Day for C=12×12/4=36

B=====12×12/3=48

A=====12×12/5=28.8