Question

A,B and C together can finish a piece of work in 4 days;A alone can do it in 12 days and B in 18 days,then C alone can do it in:

Answer 1

Here's your answer!!

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(A+B+C) one day work is 4 days.

(A+B+C)'s one day work is

$= > \frac{1}{4}$

A can do piece of work in 12 days.

One day work of A is

$= > \frac{1}{12}$

B can do piece of work in 18 days.

One day work of B is ,

$= > \frac{1}{18}$

Let B complete the work in x days.

One day work of B is ,

$= > \frac{1}{x}$
A/q

$= >( \frac{1}{12} + \frac{1}{18}) + \frac{1}{x} = \frac{1}{4}$

$= > ( \frac{3 + 2}{36}) + x = \frac{1}{4}$

$= > \frac{5}{36} + x = \frac{1}{4}$

$= > x = \frac{1}{4} - \frac{5}{36}$

$= > x = ( \frac{9 - 5}{36})$

$= > x = \frac{4}{36}$

$= > x = \frac{1}{9}$

Hence,

C can complete the work in 9 days and one day work of C is 1/9days.

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Hope it helps you!! :)