Math, asked by aparnak3101, 4 months ago

A,B and C working together can finish a piece of work in 8 hours. A alone can do it in 20 hours B alone can do it in 24 hours . In how many hours will C alone do the same work​

Answers

Answered by scprasad004
2

Answer:

ANSWER

A,B,C working together complete a work in 8 hours.

∴ In one hour they can complete

8

1

th of work.

A can alone do the work in 20hr

∴ In one hour A can complete

20

1

th of work.

B can alone do the work in 24hr.

∴ In one hour B can do

24

1

th of work.

Let in one hour C can do

x

1

th of work.

20

1

+

24

!

+

x

1

=

8

1

x

1

=

8

1

−(

20

1

+

24

1

)

=

8

1

20×24

44

=

8

1

120

11

=

120

15−11

=

120

4

=

30

1

∴ C can do the same work in 30 hours.

Answered by aryansharma91
2

Step-by-step explanation:

ANSWER

A,B,C working together complete a work in 8 hours.

∴ In one hour they can complete

8

1

th of work.

A can alone do the work in 20hr

∴ In one hour A can complete

20

1

th of work.

B can alone do the work in 24hr.

∴ In one hour B can do

24

1

th of work.

Let in one hour C can do

x

1

th of work.

20

1

+

24

!

+

x

1

=

8

1

x

1

=

8

1

−(

20

1

+

24

1

)

=

8

1

20×24

44

=

8

1

120

11

=

120

15−11

=

120

4

=

30

1

∴ C can do the same work in 30 hours.

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