A, B and C working together can finish a piece of work in 8 hours. A alone can d 20 hours and B alone can do it in 24 hours. In how many hours will C alone do the same work
Answers
Answered by
0
A+B+C = 80
A+B+C = 8020+24+C = 80
A+B+C = 8020+24+C = 80C= 8O-44
C=44
Similar questions