Question

A, B and C working togher can finish a piece of work in 8 hours. Alone can do it in 24 hours In how many hours will C alone do the same work
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Answer 1

Solution :-

Time taken by A, B and C working together to finish a work = 8 hours 

Work done by A, B and C working together in one hour = 1/8

Time taken by A alone to finish the work = 20 hours

Work done by A in 1 hour = 1/20 

Time taken by B alone to finish the work = 24 hours

Work done by B in 1 hour = 1/24

So, work done by C  = 1/8 - (1/20 + 1/24)

Taking LCM of the denominators and then solving it.

⇒ [15 - (6 + 5)]/120

⇒ (15 - 11)/120

⇒ 4/120

⇒ 1/30 

So, C alone can do the same work in 30 hours.

Answer 2

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