A, B, and Care collinear. B lies between A and C is 2/5 and C. B divides AC in the ratio 2 : 5. A lies at (–12, 2) and B lies at (-16, -2). What are the coordinates of C? C =
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0
Answer:
Since AC=2BC=>
BC
AC
=2:1
This means, C divides AB externally in the ratio 2:1
Using the section formula, if a point (x,y) divides the
line joining the points (x
1
,y
1
) and (x
2
,y
2
)externally in the ratio m:n, then (x,y)=(
m−n
mx
2
−nx
1
,
m−n
my
2
−ny
1
)
Substituting (x
1
,y
1
)=(−3,4) and (x
2
,y
2
)=(2,1) and m=2,n=1 in the section formula, we get
C=(
2−1
2(2)−1(−3)
,
2−1
2(1)−1(4)
)=(7,−2)
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