Question

a b and CD intersect at point O such that AO is equal to ob and OC is equal to OD prove that triangle ABC congruent to triangle bod​

Answer 1

In triangles AOC and BOD, we have,

AO = BO, (O, the midpoint of AB)

∠AOC = ∠BOD, (vertically opposite angles)

CO = OD, (O, the midpoint of CD)

So, by SAS congruence we have,

∆AOC ≅ ∆BOD

Hence Proved

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