Question

a b and s are points on a circle, center o ta and tb are tangents, atb =52. calculate
.aob
.oba
.asb
​

Answer 1

Step-by-step explanation:

TA and TB are tangents to circle O.

∠T=70

o

To find:

∠AOB

Solution:

Tangent and normal at a point on a circle are perpendicular to each other.

∠A=∠B=90

o

Sum of angles of a quadrilateral is 360

o

.

∠A+∠B+∠O+∠T=360

o

90

o

+90

o

+∠O+70

o

=360

o

∠O=110

o