Question

(a + b) + (aw + bw2) + (aw2 + bw) = 0​

Answer 1

Step-by-step explanation:

(a+b)=0

(aw+bw)=0

(aw2+bw2)=0 >>a+b=0

hence a=0. and b=0

Answer 2

Bro, it is as easy as rearranging. As we see a, aw, aw² in order, we can rearrange like this.

→ (a+aω+aω²)+(b+bω+bω²)=0

→ (a+b)(ω²+ω+1)=0

But your questions seems incomplete :(

If you're to solve an equation↓↓

a+b=0 or ω²+ω+1=0

If you are to use cube roots of unity↓↓

(a+b)×0=0