Math, asked by cksodi3, 9 months ago

a/b+b/a=-1 and a,b=0 then find value of a^3-b^3

Answers

Answered by shulindubey
0

Answer:

          (a^2 + b^2)/ab = 1.

          a^2 + b^2 = ab   --- (1)

Then a^3 + b^3 = (a + b)(a^2 + b^2 - ab)

                          = (a + b)(ab - ab)  (From (1))

                          = 0.

Step-by-step explanation:

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